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Fix adding pipes to periodic schedule

main
PaulStoffregen 7 年之前
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78a466c362
共有 1 個檔案被更改,包括 25 行新增3 行删除
  1. +25
    -3
      ehci.cpp

+ 25
- 3
ehci.cpp 查看文件

@@ -1093,7 +1093,7 @@ bool USBHost::allocate_interrupt_pipe_bandwidth(Pipe_t *pipe, uint32_t maxlen, u
void USBHost::add_qh_to_periodic_schedule(Pipe_t *pipe)
{
// quick hack for testing, just put it into the first table entry
println("add_qh_to_periodic_schedule:");
println("add_qh_to_periodic_schedule: ", (uint32_t)pipe, HEX);
#if 0
pipe->qh.horizontal_link = periodictable[0];
periodictable[0] = (uint32_t)&(pipe->qh) | 2; // 2=QH
@@ -1104,8 +1104,11 @@ void USBHost::add_qh_to_periodic_schedule(Pipe_t *pipe)
println(" interval = ", interval);
println(" offset = ", offset);

// TODO: does this really make an inverted tree like EHCI figure 4-18, page 93
// By an interative miracle, hopefully make an inverted tree of EHCI figure 4-18, page 93
for (uint32_t i=offset; i < PERIODIC_LIST_SIZE; i += interval) {
print(" old slot ", i);
print(": ");
print_qh_list((Pipe_t *)(periodictable[i] & 0xFFFFFFE0));
uint32_t num = periodictable[i];
Pipe_t *node = (Pipe_t *)(num & 0xFFFFFFE0);
if ((num & 1) || ((num & 6) == 2 && node->periodic_interval < interval)) {
@@ -1116,13 +1119,32 @@ void USBHost::add_qh_to_periodic_schedule(Pipe_t *pipe)
println(" traverse list ", i);
// TODO: skip past iTD, siTD when/if we support isochronous
while (node->periodic_interval >= interval) {
if (node == pipe) goto nextslot;
print(" num ", num, HEX);
print(" node ", (uint32_t)node, HEX);
println("->", node->qh.horizontal_link, HEX);
if (node->qh.horizontal_link & 1) break;
num = node->qh.horizontal_link;
node = (Pipe_t *)(num & 0xFFFFFFE0);
}
pipe->qh.horizontal_link = num;
Pipe_t *n = node;
do {
if (n == pipe) goto nextslot;
n = (Pipe_t *)(n->qh.horizontal_link & 0xFFFFFFE0);
} while (n != NULL);
print(" adding at node ", (uint32_t)node, HEX);
print(", num=", num, HEX);
println(", node->qh.horizontal_link=", node->qh.horizontal_link, HEX);
pipe->qh.horizontal_link = node->qh.horizontal_link;
node->qh.horizontal_link = (uint32_t)pipe | 2; // 2=QH
// TODO: is it really necessary to keep doing the outer
// loop? Does adding it here satisfy all cases? If so
// we could avoid extra work by just returning here.
}
nextslot:
print(" new slot ", i);
print(": ");
print_qh_list((Pipe_t *)(periodictable[i] & 0xFFFFFFE0));
}
#endif
#if 1

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